Answer :
You have to solve equation system:
[tex] \left \{ {{y=2x+6}|*(-1) \atop {y=3x+4}} \right. \\ \left \{ {{-y=-2x-6} \atop {y=3x+4}} \right. \\ 0=x-2\\ x=2[/tex]
Or you can also graph it. Look at enclose.
To graph it you have to draw two lines choosing two points for each one.
For example:
y=2x+6
so if x=0 y = 6
if x = 1 y = 8
You connect this points and you have y=2x+6 line. You do this the same with the second line.
[tex] \left \{ {{y=2x+6}|*(-1) \atop {y=3x+4}} \right. \\ \left \{ {{-y=-2x-6} \atop {y=3x+4}} \right. \\ 0=x-2\\ x=2[/tex]
Or you can also graph it. Look at enclose.
To graph it you have to draw two lines choosing two points for each one.
For example:
y=2x+6
so if x=0 y = 6
if x = 1 y = 8
You connect this points and you have y=2x+6 line. You do this the same with the second line.
Answer:
The x-coordinate of the point in the standard (x,y) coordinate plane at which the 2 lines y = 2x + 6 and y = 3x + 4 intersect is:
x=2
Step-by-step explanation:
The point of intersection of the two lines is the point where the y-value of the two lines are equal.
Now, in order to find the x-coordinate of the point of intersection we equate the equation of two lines in terms of x and by some operation we obtain the value of x.
Here the equation of two lines are:
y = 2x + 6 and y = 3x + 4
Now, on equating the y-value we have:
2x+6=3x+4
Now,
3x-2x=6-4
i.e.
x=2
Also, on putting the value of x in any of the two equation of lines we have:
y=10
Hence, the point of intersection is: (2,10)
