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An aircraft on it's take-off run has a steady acceleration of 3m/s^2. How much velocity does it gain 10 seconds?



Answer :

Acceleration measures how fast the speed changes over time.

So, over 10s, the aircraft's speed changes by 3[tex] \frac{m}{ s^{2} } [/tex] * 10s

So, the change is 30[tex] \frac{m}{s} [/tex]

Note that the one of the second units cancels out in the answer.
To solve this, let's use the formula a=(v''-v')÷(t)

3=(v''-0)÷(10)
3=v÷10

Now isolate for velocity

v"=(3)(10)
v"=30 m/s!

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