Answer :
Draw a right triangle.
[tex]tan(theta) = \frac{opposite}{adjacent}[/tex]
[tex]tan(theta) = \frac{10}{14}[/tex]
Arctangent (tan^-1) can be used to find theta.
[tex]tan^{-1}(\frac{10}{14})=theta[/tex]
[tex]theta\ is\ approx\ \boxed{36\ degrees}[/tex]
[tex]tan(theta) = \frac{opposite}{adjacent}[/tex]
[tex]tan(theta) = \frac{10}{14}[/tex]
Arctangent (tan^-1) can be used to find theta.
[tex]tan^{-1}(\frac{10}{14})=theta[/tex]
[tex]theta\ is\ approx\ \boxed{36\ degrees}[/tex]
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