Answer :
pafff
g(x)=[tex] \sqrt{x-7} [/tex]
this means if you put in 8 for x then you will get g(8)=[tex] \sqrt{8-7}= \sqrt{1}=1 [/tex]
so subsitute and solve
g(8)=[tex] \sqrt{8-7}= \sqrt{1}=1 or -1 [/tex]
g(32)=[tex] \sqrt{32-7}= \sqrt{25}=5 or -5 [/tex]
g(80)=[tex] \sqrt{80-7}= \sqrt{73}=[/tex] aprox 8.544 but √73 would be acceptable
g(x)=[tex] \sqrt{x-7} [/tex]
this means if you put in 8 for x then you will get g(8)=[tex] \sqrt{8-7}= \sqrt{1}=1 [/tex]
so subsitute and solve
g(8)=[tex] \sqrt{8-7}= \sqrt{1}=1 or -1 [/tex]
g(32)=[tex] \sqrt{32-7}= \sqrt{25}=5 or -5 [/tex]
g(80)=[tex] \sqrt{80-7}= \sqrt{73}=[/tex] aprox 8.544 but √73 would be acceptable
