Answer :
[tex](\frac{(3x + 4)}{(x + 2)})^{2} = \frac{(3x + 4)^{2}}{(x + 2)^{2}} = \frac{(3x + 4)(3x + 4)}{(x + 2)(x + 2)} = \frac{9x^{2} + 12x + 12x +16}{x^{2} + 2x + 2x + 4} = \frac{9x^{2} + 24x + 16}{x^{2} + 4x + 4} = 9 - \frac{12x - 20}{x^{2} + 4x + 4} [/tex]
