Answer :
The equation of a circle:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(h,k) - the coordinates of the center
r - the radius
[tex]\hbox{the center: } A(-3,2) \\ h=-3 \\ k=2 \\ \\ \hbox{the equation:} \\ (x+3)^2+(y-2)^2=r^2 \\ \\ \hbox{the circle passes through B(1,3)} \\ x=1 \\ y=3 \\ \Downarrow \\ (1+3)^2+(3-2)^2=r^2 \\ 4^2+1^2=r^2 \\ 16+1=r^2 \\ 17=r^2 \\ \\ \hbox{the equation is:} \\ (x+3)^2+(y-2)^2=17[/tex]
Plug the coordinates of the points into the equation and check:
[tex]C(-1,-2) \\ (-1+3)^2+(-2-2)^2=17 \\ 2^2+(-4)^2=17 \\ 4+16=17 \\ 20=17 \\ not \ true \\ \\ D(-6,3) \\ (-6+3)^2+(3-2)^2=17 \\ (-3)^2+1^2=17 \\ 9+1=17 \\ 10=17 \\ not \ true[/tex]
[tex]E(-3,-3) \\ (-3+3)^2+(-3-2)^2=17 \\ 0^2+(-5)^2=17 \\ 25=17 \\ not \ true \\ \\ F(-2,6) \\ (-2+3)^2+(6-2)^2=17 \\ 1^2+4^2=17 \\ 1+16=17 \\ 17=17 \\ true[/tex]
The answer is F(-2,6).
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(h,k) - the coordinates of the center
r - the radius
[tex]\hbox{the center: } A(-3,2) \\ h=-3 \\ k=2 \\ \\ \hbox{the equation:} \\ (x+3)^2+(y-2)^2=r^2 \\ \\ \hbox{the circle passes through B(1,3)} \\ x=1 \\ y=3 \\ \Downarrow \\ (1+3)^2+(3-2)^2=r^2 \\ 4^2+1^2=r^2 \\ 16+1=r^2 \\ 17=r^2 \\ \\ \hbox{the equation is:} \\ (x+3)^2+(y-2)^2=17[/tex]
Plug the coordinates of the points into the equation and check:
[tex]C(-1,-2) \\ (-1+3)^2+(-2-2)^2=17 \\ 2^2+(-4)^2=17 \\ 4+16=17 \\ 20=17 \\ not \ true \\ \\ D(-6,3) \\ (-6+3)^2+(3-2)^2=17 \\ (-3)^2+1^2=17 \\ 9+1=17 \\ 10=17 \\ not \ true[/tex]
[tex]E(-3,-3) \\ (-3+3)^2+(-3-2)^2=17 \\ 0^2+(-5)^2=17 \\ 25=17 \\ not \ true \\ \\ F(-2,6) \\ (-2+3)^2+(6-2)^2=17 \\ 1^2+4^2=17 \\ 1+16=17 \\ 17=17 \\ true[/tex]
The answer is F(-2,6).
