Answer :
All you gotta do is multiply the cm by 15,
For 13) you'd do [tex]2.5*15[/tex]
14) [tex]0.2*15[/tex]
15) [tex]15*15[/tex]
then for 16) [tex]4.6*15[/tex]
For 13) you'd do [tex]2.5*15[/tex]
14) [tex]0.2*15[/tex]
15) [tex]15*15[/tex]
then for 16) [tex]4.6*15[/tex]
Let
x-------> distance in the map in cm
y-------> actual distance in Km
we know that
[tex]Scale\ Map=\frac{x}{y} \\ \\ Scale\ Map=\frac{1}{15}\frac{cm}{Km}[/tex]
so
[tex]\frac{x}{y}=\frac{1}{15}[/tex]
[tex]y=15x[/tex] --------> equation [tex]1[/tex]
Part 13) find the actual distance corresponding to the scale map [tex]2.5\ cm[/tex]
In this problem we have
[tex]x=2.5\ cm[/tex]
Substitute the value of x in the equation [tex]1[/tex] to find the actual distance
[tex]y=15*2.5=37.5\ Km[/tex]
therefore
the answer part 13) is
the actual distance is [tex]37.5\ Km[/tex]
Part 14) find the actual distance corresponding to the scale map [tex]0.2\ cm[/tex]
In this problem we have
[tex]x=0.2\ cm[/tex]
Substitute the value of x in the equation [tex]1[/tex] to find the actual distance
[tex]y=15*0.2=3\ Km[/tex]
therefore
the answer part 14) is
the actual distance is [tex]3\ Km[/tex]
Part 15) find the actual distance corresponding to the scale map [tex]15\ cm[/tex]
In this problem we have
[tex]x=15\ cm[/tex]
Substitute the value of x in the equation [tex]1[/tex] to find the actual distance
[tex]y=15*15=225\ Km[/tex]
therefore
the answer part 15) is
the actual distance is [tex]225\ Km[/tex]
Part 16) find the actual distance corresponding to the scale map [tex]4.6\ cm[/tex]
In this problem we have
[tex]x=4.6\ cm[/tex]
Substitute the value of x in the equation [tex]1[/tex] to find the actual distance
[tex]y=15*4.6=69\ Km[/tex]
therefore
the answer part 16
the actual distance is [tex]69\ Km[/tex]
