a bottle contains 12 red marbles and 8 blue marbles. A marble is chosen at random and not replaced. Then a second marble is chosen at random. Determine the probability that the two marbles are not the same color.



Answer :

[tex]P(A)= \frac{12}{20} \cdot \frac{8}{19} + \frac{8}{20} \cdot \frac{12}{19}= \frac{12\cdot8}{20\cdot19} \cdot2=\frac{12\cdot4}{5\cdot19}= \frac{48}{95} [/tex]
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