Answer :

in this equation we start by filling in the N with "1" then"2" then "3" and so on

3n+4=
3(1)+4=7
3(2)+4=10
3(3)+4=13
3(4)+4=16
AyaZ
[tex] x_{n} =3n + 4 \\ x_{1} =3(1) + 4=7 \\ x_{2} =3(2) + 4=10 \\ x_{3} =3(3) + 4=13 \\ x_{4} =3(4) + 4 =16\\ x_{5} =3(5)+ 4 =19\\ [/tex]

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