The area tjhat he can cover with these tiles is 77 ¹¹/₃₂ in²
To solve the above questions, we need to recall some of the formulas as follows:
Area of Square = (Length of Side)²
Perimeter of Square = 4 × (Length of Side)
Area of Rectangle = Length × Width
Perimeter of Rectangle = 2 × ( Length + Width )
Area of Rhombus = ½ × ( Diagonal₁ + Diagonal₂ )
Perimeter of Rhombus = 4 × ( Length of Side )
Area of Kite = ½ × ( Diagonal₁ + Diagonal₂ )
Perimeter of Kite = 2 × ( Length of Side₁ + Length of Side₂ )
Let us now tackle the problem !
Given:
Number of Tiles = N = 9 tiles
Length of Tiles = L = 3¹/₈ inches
WIdth of Tiles = W = 2³/₄ inches
Unknown:
Total Area = A = ?
Solution:
Area of One Tile.
[tex]\texttt{Area of Rectangle} = \texttt{Length} \times \texttt{Width}[/tex]
[tex]\texttt{Area of Rectangle} = 3 \frac{1}{8} \times 2 \frac{3}{4}[/tex]
[tex]\texttt{Area of Rectangle} = 8 \frac{19}{32} ~ \texttt{in}^2[/tex]
Total Area.
[tex]\texttt{Total Area} = \texttt{Number of Tiles} \times \texttt{Area of One Tile}[/tex]
[tex]\texttt{Total Area} = 9 \times 8 \frac{19}{32}[/tex]
[tex]\texttt{Total Area} = 77 \frac{11}{32} ~ \texttt{in}^2[/tex]
Grade: College
Subject: Mathematics
Chapter: Two Dimensional Figures
Keywords: Perimeter, Area , Square , Rectangle , Side , Length , Width
