Answer :
0.6 dm3 x 1.1 dm3
= 0.66 Mols required
If density of water and KNO3 are said to be equal:
then mass = mol x rmm
= 0.66 x 101.1
= 66.73 grams (to 4 sf)
= 0.66 Mols required
If density of water and KNO3 are said to be equal:
then mass = mol x rmm
= 0.66 x 101.1
= 66.73 grams (to 4 sf)