Answer :
Get y by itself to be in slope-intercept form, which is: y=mx+b
m=slope
b=y-intercept
To do that subtract 2x from both sides to get: 5y=-2x+8. You're not done yet because y still isn't by itself so you divide both sides by five and you get: y= -2/5x+8/5
m= -2/5 which is the slope so the slope is equal to -2/5
m=slope
b=y-intercept
To do that subtract 2x from both sides to get: 5y=-2x+8. You're not done yet because y still isn't by itself so you divide both sides by five and you get: y= -2/5x+8/5
m= -2/5 which is the slope so the slope is equal to -2/5
First thing, you need to transform this equation to the form of y = ax + b
So you get:
2x + 5y = 8
5y = -2x + 8
[tex]y = -\frac{2}{5} x + \frac{8}{5} [/tex]
In the form of y = ax + b, a is the slope.
In [tex]y = -\frac{2}{5} x + \frac{8}{5} [/tex], you can see "[tex]- \frac{2}{5} x[/tex]", and always the number before x is the slope
So, the slope of 2x + 5y = 8 is [tex]- \frac{2}{5}[/tex]
Hope this Helps :)
So you get:
2x + 5y = 8
5y = -2x + 8
[tex]y = -\frac{2}{5} x + \frac{8}{5} [/tex]
In the form of y = ax + b, a is the slope.
In [tex]y = -\frac{2}{5} x + \frac{8}{5} [/tex], you can see "[tex]- \frac{2}{5} x[/tex]", and always the number before x is the slope
So, the slope of 2x + 5y = 8 is [tex]- \frac{2}{5}[/tex]
Hope this Helps :)
