Answer :
The volume of a cone:
[tex]V=\frac{1}{3} \pi r^2h[/tex]
r - the radius
h - the height
[tex]r=6 \\ h=10 \\ \\ V=\frac{1}{3} \pi \times 6^2 \times 10=\frac{1}{3} \pi \times 36 \times 10=\frac{360}{3} \pi=120\pi[/tex]
The answer is B. 120π in³.
[tex]V=\frac{1}{3} \pi r^2h[/tex]
r - the radius
h - the height
[tex]r=6 \\ h=10 \\ \\ V=\frac{1}{3} \pi \times 6^2 \times 10=\frac{1}{3} \pi \times 36 \times 10=\frac{360}{3} \pi=120\pi[/tex]
The answer is B. 120π in³.
Answer: Option 'B' is correct.
Step-by-step explanation:
Since we have given that
Radius of cone = 6 inches
Height of cone = 10 inches
We need to find the "volume of cone":
As we know the formula for "Volume of cone":
[tex]Volume=\frac{1}{3}\pi r^2h\\\\Volume=\frac{1}{3}\pi \times 6\times 6\times 10\\\\Volume=120\pi\ cm^3[/tex]
Hence, Exact volume of cone is 120π cm³.
Therefore, Option 'B' is correct.
