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A machine has a mechanical advantage of 5. if 300 newtons of input force is used to produce 3,000 newton meters of work what is the output force and what is the distance over which the work is applied



Answer :

F(in) x d(in)= F(out)x d(out)
A machine has a mechanical advantage of 5.
F(out )= 5xF(in)300 newtons

F(in) = 300 N
F(out)= 5xF(in) = 5x300 N
= 1500 N

Work in = Work out = 3000 N x m3000
N x m = F_in x d_ind_in = 3000 Nxm / F_in = 3000 N x m / 300 N = 10 m3000 Nxm = F_out x d_out d_out = 3000 Nx m / F_out = 3000 N x m / 1500 N = 2 m

Answer:

D. 3600 N

Explanation:

On edg.

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