Answer :
subsitution
x=3y+5
x-4y=3
we know that x=3y+5 so subsitute 3y+5 for x in second equation
3y+5-4y=3
5-y=3
subtract 5 from both sides
-y=-2
multiply -1
y=2
subistute 2 for y in first equationx=3y+5
x=3(2)+5
x=6+5
x=11
x=11
y=2
in (x,y) form
(11,2)
x=3y+5
x-4y=3
we know that x=3y+5 so subsitute 3y+5 for x in second equation
3y+5-4y=3
5-y=3
subtract 5 from both sides
-y=-2
multiply -1
y=2
subistute 2 for y in first equationx=3y+5
x=3(2)+5
x=6+5
x=11
x=11
y=2
in (x,y) form
(11,2)
