Answer :
You need to add the last substance to the products side(the right sode of the arrow). You have hydrogen and oxygen - water.
You get: BrO3 + N2H4 -> Br2 + N2 + H2O
# of Br: 1x1 = 1 # of Br: 2x1 = 2
O: 3x1 = 3 O: 1x1 = 1
N: 2x1 = 2 B N: 2x1 = 2
H: 4x1 = 4. H: 2x1 = 2
Br:
Multiply the reactant (left) side by 2 to balance.
O:
You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.
H:
The product side is now equal to 12. Multiply the reactant side by 3 to balance.
N:
Now you have to balance N because the reactant side has been risen. So multiply the product side by three as well.
You end up with the complete and balanced equation:
2BrO3 + 3N2H4 -> Br2 + 3N2 + 6H2O
You get: BrO3 + N2H4 -> Br2 + N2 + H2O
# of Br: 1x1 = 1 # of Br: 2x1 = 2
O: 3x1 = 3 O: 1x1 = 1
N: 2x1 = 2 B N: 2x1 = 2
H: 4x1 = 4. H: 2x1 = 2
Br:
Multiply the reactant (left) side by 2 to balance.
O:
You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.
H:
The product side is now equal to 12. Multiply the reactant side by 3 to balance.
N:
Now you have to balance N because the reactant side has been risen. So multiply the product side by three as well.
You end up with the complete and balanced equation:
2BrO3 + 3N2H4 -> Br2 + 3N2 + 6H2O
The balanced chemical reaction will be [tex]2BrO_{3}(aq) +3N_{2} H_{4} (aq)[/tex] → [tex]Br_{2}(l) +3N_{2}(g) +6H_{2}O(l)[/tex].
What is balanced chemical reaction?
An equation for such a chemical reaction can be said to be balanced when both the reactants and even the products have the same quantity of atoms and the total charge for each component of the reaction. In other words, each sides of the reaction have an equal balance of mass as well as charge. Such reaction will be referred as balanced chemical reaction.
The given un-balanced chemical reaction is
[tex]BrO_{3}(aq) +N_{2} H_{4} (aq)[/tex] → [tex]Br_{2}(l) +N_{2}(g)[/tex].
It can be seen that count of Br atom in reactant side is only one where 2 Br atom is present in product side.
By multiply by 2 in the reactant side of Br and by 3 in [tex]N_{2} H_{4}[/tex] then equation will be balanced.
Therefore, the balanced chemical equation can be written as:
[tex]2BrO_{3}(aq) +3N_{2} H_{4} (aq)[/tex] → [tex]Br_{2}(l) +3N_{2}(g) +6H_{2}O(l)[/tex].
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