Answer :
What we are going to do is add [tex] \frac{1}{2} [/tex] by [tex] \frac{2}{3} [/tex]. The first thing we do is make common denominators for [tex] \frac{1}{2} [/tex] and [tex] \frac{2}{3} [/tex]:[tex] \frac{1*3}{2*3}= \frac{3}{6} \ and \ \frac{2*2}{3*2}= \frac{4}{6} [/tex]. Now we add [tex] \frac{3}{6}[/tex] by [tex] \frac{4}{6} [/tex]: [tex] \frac{3}{6}+ \frac{4}{6}= \frac{7}{6}[/tex]. Now we make [tex] \frac{7}{6}[/tex] a mixed number:[tex] \frac{7}{6}=1 \frac{1}{6}[/tex]. Therefore, your answer is [tex]\boxed{\boxed{1 \frac{1}{6}}}[/tex]. Hoped I helped. :)
so first convert the denoenator (bottom n umber) to the sam enumber
1/2 and 2/3
the numbers are 2 and 3
find least comon multiple
easy way to convert is multiply each by bottom number of the other over the other exg
1/2 +2/3
1/2 times 3/3+2/3 times 2/2
3/6+4/6
(7)/6
7/6
1 and 1/6
1/2 and 2/3
the numbers are 2 and 3
find least comon multiple
easy way to convert is multiply each by bottom number of the other over the other exg
1/2 +2/3
1/2 times 3/3+2/3 times 2/2
3/6+4/6
(7)/6
7/6
1 and 1/6
