So. Allow me to justify what i just did.
First line: by definition, tangent in sine/cosine, and cotangent is the reciprocal of that.
Second line: You have to multiply by ([tex] \frac{sin cos}{sincos} [/tex]) to get a common denominator, so you get the second line.
Third line: Canceling stuff out. to get that.
Fourth line: Adding them together since they now have common denominators.
Fifth line: By terms of the pythagorean identity, [tex] sin^{2} [/tex]+[tex] cos^{2} [/tex]=1. so that is equal to the right side.
Thus verified.
