Answer :
Plug the values into the equation and check:
[tex](1,4) \\ x=1 \\ y=4 \\ \Downarrow \\ y=2x+1 \\ 4=2 \times 1+1 \\ 4=2+1 \\ 4=3 \\ \hbox{not true}[/tex]
The answer is A. No, because the ordered pair does not fit the equation.
[tex](1,4) \\ x=1 \\ y=4 \\ \Downarrow \\ y=2x+1 \\ 4=2 \times 1+1 \\ 4=2+1 \\ 4=3 \\ \hbox{not true}[/tex]
The answer is A. No, because the ordered pair does not fit the equation.
Let's try to put the pair into the equation:
x is the first number, and y is the second.
4=2*1+1
Let's perform the operations on the right:
2*1=2
2+1=3
so the left side is 3.
now, that would mean that the equation is 4=3, which is false! so the answer is A: does not fut the equation.
x is the first number, and y is the second.
4=2*1+1
Let's perform the operations on the right:
2*1=2
2+1=3
so the left side is 3.
now, that would mean that the equation is 4=3, which is false! so the answer is A: does not fut the equation.
