Answer :
[tex]v=2.25` 10^{8} \frac{m}{s} [/tex]
N=1.33 being the Index of Refraction of a material and [tex]c=3.0` 10^{8} \frac{m}{s} [/tex] the speed of light in vacuum you get:
[tex]v= \frac{c}{N}= \frac{3.0 10^{8} }{1.33}=2.25` 10^{8} \frac{m}{s} [/tex] speed of light in that material.
N=1.33 being the Index of Refraction of a material and [tex]c=3.0` 10^{8} \frac{m}{s} [/tex] the speed of light in vacuum you get:
[tex]v= \frac{c}{N}= \frac{3.0 10^{8} }{1.33}=2.25` 10^{8} \frac{m}{s} [/tex] speed of light in that material.
If the refractive index of some substance is 1.33, then
the speed of light in that substance is
(speed of light in vacuum) / (1.33) =
(299,792,458 m/s) / (1.33) = 225,407,863 m/s
