Answer :

AyaZ
[tex] \frac{1}{12} + \frac{3}{8} = \frac{1*4}{12*4} + \frac{3*6}{8*6}= \frac{4}{48} + \frac{18}{48}= \frac{4+18}{48} = \frac{22}{48} = \frac{11}{24} [/tex]
[tex]^{2)} \frac{1}{12}+ ^{3)}\frac{3}{8}= \frac{2}{24}+ \frac{9}{24}= \bold{\frac{11}{24}} [/tex]

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