Answer :

Number A: n

Number B: (n-1)

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Let's search for the value of (n) to find the number A and B...

[tex]n+\left( n-1 \right) =n+1\\ \\ n+n-1=n+1\\ \\ 2n-1=n+1\\ \\ 2n-n=2\\ \\ n=2[/tex]

If n=2,

Number A = 2

Number B = 1

The two consecutive numbers are 1 and 2.

Answer:

(n/2) and (n/2+1)

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