Answer :
It would be (x)(x+7)=170
If you want it solved, then you would get:
[tex] x^{2} +7x-170[/tex]=0
(x+17)(x-10)=0
And since you can't have a negative length (-17), x=10
So your side lengths would be 10 and 17 (10+7), which would give you an area of 170.
Hope that helps.
If you want it solved, then you would get:
[tex] x^{2} +7x-170[/tex]=0
(x+17)(x-10)=0
And since you can't have a negative length (-17), x=10
So your side lengths would be 10 and 17 (10+7), which would give you an area of 170.
Hope that helps.
Answer:
Step-by-step explanation:
Let the length of the rectangle be=x, then the width of he rectangle will be=7+x.
Also, we are given that the area of the rectangle is equal to=170 square meters, therefore
Area of rectangle=Length×Width
⇒[tex]170=x(x+7)[/tex]
On solving the above equation, we get
⇒[tex]170=7x+x^2[/tex]
⇒[tex]x^2+7x-170=0[/tex]
which is the required quadratic equation.
⇒[tex]x^2+17x-10x-170=0[/tex]
⇒⇒[tex]x(x+17)-10(x+17)=0[/tex]
⇒[tex](x+17)(x-10)=0[/tex]
Since, he length of the rectangle cannot be negative, therefore the length of the rectangle=x=10 m
And, the width is=x+7=10+7=17meters.
