parkalexandria parkalexandria

02-06-2015
Mathematics

Answered

find the eccentricity of the ellipse
4x^2 +16y^2 +32x-32y+16=0

Answer :

Panoyin Panoyin

03-06-2015

       4x² + 16y² + 32x - 32y + 16 = 0
    - 16 - 16
           4x² + 16y² + 32x - 32y = -16
           4x² + 32x + 16y² - 32y = -16
4(x² + 8x + 16) + 16(y² - 2y + 1) = -16 + 4(16) + 16(1)
      4(x + 4)² + 16(y - 1)² = -16 + 64 + 16
      4(x + 4)² + 16(y - 1)² = 48 + 16
      4(x + 4)² + 16(y - 1)² = 64
        64     64     64
      (x + 4)² + (y - 1)² = 1
   16 2

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