Answer:
(4) 90.°
Explanation:
The maximum height reached by the ball depends on the vertical velocity of the ball: the greater the vertical velocity of the ball, the higher the ball will go.
The vertical component of the velocity of the ball is given by:
[tex]v_y = v_0 sin \theta[/tex]
where
[tex]v_0 = 10 m/s[/tex] is the initial speed of the ball
[tex]\theta[/tex] is the angle at which the ball is thrown
Therefore, [tex]v_y[/tex] will be maximum when [tex]sin \theta =1[/tex]. And by solving this equation, we find that the angle that satisfies this condition is [tex]\theta=90^{\circ}[/tex], which corresponds to throwing the ball straight up.
