The radioactive element​ carbon-14 has a​ half-life of 5750 years. A scientist determined that the bones from a mastodon had lost 85.2​% of their​ carbon-14. How old were the bones at the time they were​ discovered?



Answer :

Answer:

To determine the age of the bones, we can use the formula for exponential decay:

N(t) = N0 * (1/2)^(t/T)

Where:

N(t) = the amount of substance remaining after time t

N0 = the initial amount of substance

t = time that has passed

T = half-life of the substance

Given that 85.2% of carbon-14 has decayed, 14.8% remains. We can express this as a fraction: 0.148.

So, we have:

0.148 = 1 * (1/2)^(t/5750)

Solving for t:

(1/2)^(t/5750) = 0.148

Taking the natural logarithm of both sides:

ln((1/2)^(t/5750)) = ln(0.148)

(t/5750) * ln(1/2) = ln(0.148)

Solving for t:

t = 5750 * ln(0.148) / ln(1/2)

t ≈ 19060 years

Therefore, the bones were approximately 19,060 years old at the time they were discovered.

Step-by-step explanation:

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