Answer :
the sets that could be the side lengths in a right triangle are A)
8
,
20
,
25
8,20,25, B)
9
,
40
,
41
9,40,41, and D)
6
,
30
,
31
6,30,31.
8
,
20
,
25
8,20,25, B)
9
,
40
,
41
9,40,41, and D)
6
,
30
,
31
6,30,31.
Answer:
The Answer is B) 9,40,41
Step-by-step explanation:
To solve this, all you need to do is apply Pythagoras theorem which
[tex]c^{2} =a^{2} +b^{2}[/tex] hence
[tex]c=\sqrt{a^{2}+b^{2} }[/tex] if we apply a little algebra and square root both sides.
c represents the hypotenuse which is the longest side.
a and b represent the other 2 smaller sides.
This is multiple choice all we need to do is ensure that when we square the 2 smaller sides, add them together and square root it, we get the third number.
Starting with A)
[tex]\sqrt{8^{2}+20^{2} }[/tex] is equal to 21.5.
21.5 is not equal to 25
hence 8,29 and 25 are not lengths of a right angled triangle.
B)
[tex]\sqrt{9^{2} +41^{2} }[/tex] is equal to 41
41 is equal to 41
hence 9,40 and 41 are lengths of a right angled triangle.
C)
[tex]\sqrt{10^{2} +40^{2} }[/tex] is equal to 41.2
41.2 is not equal to 45
hence 10,40 and 45 are not lengths of a right angled triangle.
D)
[tex]\sqrt{6^{2} +30^{2} }[/tex] is equal to 30.6
30.6 is not equal to 31
hence 6,30 and 41 are not lengths of a right angled triangle.
Hopefully this helped :)
