Answer :

Itz5151

Answer:

3(x-y)(y-z)(z-x)

Step-by-step explanation:

Let a = x-y,b = y-z,c = z-x

Then a+b+c = x-y+y-z+z-x =0

As a+b+c = 0 So a³+b³+c³ = 3abc

Put in the values

= 3(x-y)(y-z)(z-x)

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