Answer:
800 m.
Explanation:
To find the ground distance the plane travels as it moves 2500 m through the air, we can use trigonometry. Specifically, we can use the sine function, which is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse.
In this case, the angle of elevation is 18 degrees, and the length of the hypotenuse (the distance the plane travels through the air) is 2500 m. We want to find the length of the side opposite the angle, which is the ground distance the plane travels.
Using the sine function, we can write:
sin(18 degrees) = opposite / hypotenuse
sin(18 degrees) = ground distance / 2500 m
Solving for the ground distance, we get:
ground distance = sin(18 degrees) * 2500 m
Using a calculator, we find that sin(18 degrees) is approximately 0.309. Therefore, the ground distance is:
ground distance = 0.309 * 2500 m
ground distance = 772.5 m
Rounding to the nearest 100 m, we get:
ground distance = 800 m
Therefore, the ground distance the plane travels as it moves 2500 m through the air is approximately 800 m.