Answer :
Answer: The dimensions of the ticket are 22 centimeters by 12 centimeters.
Step-by-step explanation: This problem involves solving a system of two equations. The first equation is derived from the given perimeter of the ticket, and the second equation is derived from the given area of the ticket. The perimeter of a rectangle is given by the formula P = 2(l + w), where l is the length and w is the width. In this case, we know that P = 70 cm, so we can write the equation as 70 = 2(l + w).The area of a rectangle is given by the formula A = l*w, where l is the length and w is the width. In this case, we know that A = 264 cm^2, so we can write the equation as 264 = l*w.We can solve this system of equations by first solving the perimeter equation for one of the variables, and then substituting that expression into the area equation. From the perimeter equation, we can solve for l: l = 35 - w. Substituting this into the area equation gives us: 264 = (35 - w)*w. Solving this quadratic equation for w gives us the width of the ticket. Substituting this value back into the equation for l gives us the length of the ticket.
