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Two points located on JK are J(6,1) and K(-3,8). What is the slope of "JK"?
OA. -
O B. -
○ C.
O D.
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Answer :

GinnyAnswer
I'd be happy to help! To find the slope of the line segment JK that passes through points J(6,1) and K(-3,8), you can use the formula for slope: Slope (m) = (y2 - y1) / (x2 - x1) 1. Assign coordinates: Let J(6,1) be (x1, y1) and K(-3,8) be (x2, y2). 2. Substitute the coordinates into the formula: m = (8 - 1) / (-3 - 6) m = 7 / -9 3. Simplify the fraction: m = -7/9 Therefore, the slope of the line JK is -7/9. The correct answer is not provided in the options, so the correct answer would be: The slope of JK is -7/9.

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