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Find the slope of a line parallel to the line whose equation is 8a+ 10y=60. Fully simplify
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Apr 27
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GinnyAnswer
To find the slope of a line parallel to the equation 8a + 10y = 60, we need to rewrite the equation in slope-intercept form, which is y = mx + b, where m is the slope. Given equation: 8a + 10y = 60 First, isolate y: 10y = -8a + 60 y = -8/10*a + 6 y = -4/5*a + 6 Now, the slope of the given line is -4/5. For lines that are parallel, their slopes are the same. Therefore, the slope of a line parallel to this one is also -4/5. So, the slope of a line parallel to the equation 8a + 10y = 60 is -4/5.

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