Given f(x) = 7x³, find f¹(x). Then state whether f¹(x) is a function.
a.
X
y =
f¹(x) is a function.
7
b.
y=
d.
|
y=
+ | א
f(x)
is not a function.
f(x) is not a function.
f(x) is a function.



Answer :

Given f(x) = 7x³, to find f¹(x) which represents the inverse function, we need to swap the x and y variables and solve for y. 1. Start with the equation f(x) = 7x³ 2. Replace f(x) with y: y = 7x³ 3. Swap x and y to get x = 7y³ 4. Solve for y by taking the cube root of both sides: y = (x/7)^(1/3) Now, to determine if f¹(x) is a function, we need to check if for every x-value in the domain of f(x), there exists a unique y-value in the range of f(x). In this case, f¹(x) = (x/7)^(1/3) is a function because for every x in its domain (all real numbers), there is a unique y-value associated with it. Each x-value corresponds to only one y-value, satisfying the definition of a function. Therefore, the correct answer is: f(x) is a function.

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