Answer:
y = -10/3
Step-by-step explanation:
So the function f(x) is composed of two other functions,
12/x - 2 and -4x-14
Now each of these functions have their respective domains where x can also be within those values.
Our given x is -9, now using this value, where can I apply this?
Well, our second equation only has x values that are more than 3, so x = -9 cannot be used there, whereas our first function has a domain where all x values are less than or equal to 3. Since -9 is less than 3, thats perfect! We can use this function
Therefore
lets plug in x = -9 to 12/x - 2
12/-9 -2 = 4/-3 - 2 =-10/3
Hope that answers your question
Answer:
f(- 9) = - [tex]\frac{10}{3}[/tex]
Step-by-step explanation:
To evaluate the function at x = - 9, in the interval x ≤ 3
Then using
f(x) = [tex]\frac{12}{x}[/tex] - 2 , substitute x = - 9
f(- 9) = [tex]\frac{12}{-9}[/tex] - 2
= - [tex]\frac{4}{3}[/tex] - 2
= - [tex]\frac{4}{3}[/tex] - [tex]\frac{6}{3}[/tex]
= - [tex]\frac{10}{3}[/tex]