Answer :
To solve the problem, let's go through the calculations step-by-step to find out how many milliliters (mL) of the oil would contain 0.01 gram of dioxin.
Firstly, we need to understand what ppm means. Ppm stands for "parts per million" and is a way to express very dilute concentrations of substances. One ppm is equivalent to 1 milligram of a substance in 1 kilogram of a mixture. However, our sample of oil has a density of 0.89 grams per mL, so we will need to take that into account.
Given the contamination level is 2 ppm, this means there are 2 milligrams of dioxin in every million milligrams (or 1 kilogram) of oil.
Let's find out how many grams of dioxin are in 1 gram of oil:
2 ppm dioxin = 2 mg dioxin / 1,000,000 mg oil = 2 * 10^-6 g dioxin / 1 g oil
Since the oil has a density of 0.89 g/mL, 1 gram of oil is less than 1 mL. To find out how many grams of dioxin are in one mL of oil:
Amount of dioxin in grams per 1 mL of oil:
= density of oil * (amount of dioxin per g of oil)
= 0.89 * 2 * 10^-6
= 1.78 * 10^-6 g/mL
Now we have the concentration of dioxin in grams per milliliter of oil. To find out how many milliliters of oil are needed to get 0.01 gram of dioxin, we will divide the total amount of dioxin we want by the concentration to find the volume.
Volume of oil in mL required for 0.01 gram of dioxin:
= (amount of dioxin we want in g) / (concentration in g/mL)
= 0.01 g / (1.78 * 10^-6 g/mL)
= 0.01 / 1.78 * 10^-6
= 0.01 / 0.00000178
= 5617.98 mL approximately
Therefore, you would need approximately 5617.98 mL of this contaminated oil to have a total of 0.01 gram of dioxin.
