Answer :
Answer:
No
Step-by-step explanation:
To check if the point (-6, 10) is a solution to the system of equations, we need to substitute the values of x and y into each equation and see if the equations are true.
Given the system of equations:
1. y = [tex]-\frac{1}{3}x + 8[/tex]
2. y = [tex]-\frac{5}{2}x - 5[/tex]
Substitute x = -6 and y = 10 into each equation:
For the first equation:
10 = [tex]-\frac{1}{3}(-6) + 8[/tex]
10 = 2 + 8
10 = 10
For the second equation:
10 = [tex]-\frac{5}{2}(-6) - 5[/tex]
[tex]10 = \frac{15}{2} - 5\\\\10 = \frac{15}{2} - \frac{10}{2}\\\\10 = \frac{5}{2}[/tex]
As we can see, for the first equation, the left side equals the right side (both are 10), and for the second equation, the left side does not equal the right side (10 is not equal to 5/2).
So, (-6, 10) is not a solution to the system of equations.
