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Sophia exerts a steady 30-N horizontal force on a 7.8-kg box resting on a lab bench. The box slides against a horizontal friction force of 21 N. Find the box acceleration



Answer :

audreyn06

Answer: 1.15 m/s²

Explanation:

First, let's find the net force that the box experiences:

F = Applied force - friction force

F = 30 N - 21 N

F = 9 N

Now, we can use Newton's second law of motion to find the acceleration of the box:

F = ma, where m is the mass and a is the acceleration.

Substituting the net force and mass of the box:

9 = 7.8a

Solve for a:

a = 9/7.8

a = 1.15 m/s²

The acceleration of the box is 1.15 m/s².

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