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Given the hexagonal pyramid below, if h = 14, s = 8, and a = 4√√√3 what is the volume of the pyramid? Round
to the nearest hundredth (be sure to wait until the end of the problem to round).

Given the hexagonal pyramid below if h 14 s 8 and a 43 what is the volume of the pyramid Round to the nearest hundredth be sure to wait until the end of the pr class=


Answer :

olumideolawoyin

Answer:

2327.88

Step-by-step explanation:

Base area =

[tex] \frac{1}{2} \times a \times p[/tex]

where a = apothem = 4√3 and p = perimeter = 6 × 8 = 48

Therefore,

Base area =

[tex] \frac{1}{2} \times 4 \sqrt{3} \times 48 = 2 \sqrt{3} \times 48 = 96 \sqrt{3} [/tex]

Base area = 96√3

Hence,

Volume of the pyramid = Base area × height

= 96√3 × 14 = 1344√3

= 2327.8762

= 2327.88 to nearest hundredth

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