Answer :
Answer:
2x² + 77x (square inches)
Step-by-step explanation:
The area of the wall covered by both posters is the sum of the areas covered by each poster
Each poster has a rectangular shape
The area of a rectangle of length L and width W inches is their product: LW
The length of each poster is L = x inches
Area of the first poster
The first poster has length L = x inches and width W = x + 22 inches
Therefore the area of the first poster = LW
= x (x + 22)
= x² + 22x (square inches)
Area of second poster
The length of the second poster is L = x inches and width W = x + 55 inches
Area of second poster = LW
= x ( x + 55)
= x² + 55x (square inches)
Total of both areas
Total area covered by both posters
= (x² + 22x) + (x² + 55x)
= x² + 22x + x² + 55x
= x² + x² + 22x + 55x grouping like terms
= 2x² + 77x add like terms
Answer: 2x² + 77x (square inches)
