7) A dog trainer wants to select 2 dogs to train from
a kennel of 6. In how many ways can she choose
2 dogs from the 6 total?
A. 8
B. 12
C. 15
D. 36



Answer :

Answer:

C. 15

Step-by-step explanation:

The number of ways to choose k elements from a set of n elements is given by the formula for combinations:

[tex]C(n,k) = \dfrac{n!}{k!(n-k)!}[/tex]

Where:

n is the total number of elements (6 dogs in this case)

k is the number of elements to choose (2 dogs in this case)

"!" denotes factorial

Plugging in n = 6, k =2 we get

[tex]C(6,2) = \dfrac{6!}{2!(6-2)!}\\\\=\dfrac{6!}{2!\;4!}\\\\\\= \dfrac{6 * 5 * 4 * 3 * 2* 1}{(2*1 )(4*3*2*1)}\\\\= \dfrac{30}{2}\\\\= 15[/tex]

Therefore, the dog trainer can choose 2 dogs from the kennel of 6 in 15 ways.

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