Answer :
Sure! To write the balanced equation, we need to know the chemical formula of the compound formed by the reaction of calcium and phosphorus. Calcium typically forms Ca^2+ ions, and phosphorus typically forms P^3- ions. Therefore, the compound formed could be calcium phosphide (Ca3P2). The balanced equation for the synthesis reaction is:
3Ca + 2P -> Ca3P2
Now, to find out how many moles of product are produced, we first need to convert the mass of calcium (80.2g) to moles using its molar mass.
The molar mass of calcium (Ca) is approximately 40.08 g/mol.
Number of moles of calcium = Mass of calcium / Molar mass of calcium
= 80.2g / 40.08 g/mol
≈ 2 moles
From the balanced equation, we can see that 3 moles of calcium react to produce 1 mole of calcium phosphide. Therefore, if 2 moles of calcium produce 1 mole of calcium phosphide, then 2/3 of a mole of calcium would produce 1/3 of a mole of calcium phosphide.
So, the number of moles of product produced would be approximately 1/3 moles.
3Ca + 2P -> Ca3P2
Now, to find out how many moles of product are produced, we first need to convert the mass of calcium (80.2g) to moles using its molar mass.
The molar mass of calcium (Ca) is approximately 40.08 g/mol.
Number of moles of calcium = Mass of calcium / Molar mass of calcium
= 80.2g / 40.08 g/mol
≈ 2 moles
From the balanced equation, we can see that 3 moles of calcium react to produce 1 mole of calcium phosphide. Therefore, if 2 moles of calcium produce 1 mole of calcium phosphide, then 2/3 of a mole of calcium would produce 1/3 of a mole of calcium phosphide.
So, the number of moles of product produced would be approximately 1/3 moles.
Answer:
'In this synthesis reaction, calcium (Ca) reacts with phosphorus (P) to form a compound. The balanced chemical equation for this reaction is: Ca + P → Ca3P2 To calculate the number of moles of the product, we need to find the number of moles of calcium first: 80.2 g Ca × (1 mol Ca / 40.08 g Ca) = 2.00 mol Ca From the reaction equation, we know that every 3 moles of calcium (Ca) react with 2 moles of phosphorus (P) to produce 1 mole of the compound (Ca3P2). Therefore, the number of moles of the product resulting from this reaction is: 2.00 mol Ca × (1 mol Ca3P2 / 3 mol Ca) = 0.667 mol Ca3P2
Explanation:
