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Mg + Cl2 >> MgCl2

When 20.0 grams of solid magnesium react with 50.0 grams of chlorine gas, the chlorine gas is the limiting reactant. What mass of solid magnesium chloride forms during the reaction?

[?] g MgCl2 form



Answer :

BrotherGoku

Answer:

67.1g MgCl2

Explanation:

So first make an ICE table (Initial, Change, Equilibrium), then convert everything you have to moles. Since we know that cl2 is the limiting reagent, that means you subtract the moles Cl2 from reactant, and add it to MgCl2. Its the first substance to get completely consumed. Therefore, number of moles of Cl2 reacted = number of moles MgCl2 produced. It makes sense cause you need both of these substances together to produce MgCl2, and running out of them will stop the reaction. Lets go

20.0g x (1mol/24.305g) = 0.823mol Mg

50.0g x (1mol/70.90g) = 0.705mol Cl2

         Mg           +            Cl2              =            MgCl2

I        0.823                    0.705                            0

C      -0.705                  -0.705                           +0.705

E       0.118                         0                              0.705

0.705mol of MgCl2 produced

0.705mol x (95.211g/mol) = 67.124g = 67.1g MgCl2 (3 s.f.)

Hope that answers your question

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