Answer :
To determine whether you can draw no triangles, only one triangle, or more than one triangle with the given sides and nonincluded angle, we need to consider the possible positions of the sides and the corresponding angles.
We have a known side `a = 15 units`, another known side `b = 9.5 units`, and a known angle `C = 75°`. We are considering arranging these to form a triangle.
We would use the Law of Sines, which states that for any triangle, the ratio of the length of a side to the sine of its opposite angle is the same for all three sides.
The Law of Sines is:
sin(A)/a = sin(B)/b = sin(C)/c
Given that we have side `a`, side `b`, and angle `C`, we can find the ratio of `sin(C)` to the opposite side (which we'll call `c`):
sin(C) / c = sin(A) / a
Where A is the angle opposite side `a`.
Now we will employ this relationship to determine if a triangle can exist, and if so, how many.
Step 1. Convert angle C to radians since the sine function in trigonometry uses radians:
angle_C = 75°
Convert to radians by multiplying by π/180:
angle_C_rad = 75 × (π/180)
Step 2. Calculate sin(C):
sin(C) = sin(angle_C_rad)
Since we don't have an exact value of sin(75°) without a calculator, we'll continue in a general sense.
Step 3. Calculate the ratio, which is b sin(C) / a:
ratio = b sin(C_rad) / a
Step 4. Analyze the ratio:
If the ratio = 1, then angle A is 90° and there is exactly one right-angled triangle that can be formed.
If the ratio > 1, then no triangle can be formed, as the side `a` is not long enough to create a triangle with side `b` and angle `C`.
If the ratio is between 0 and 1, then two different triangles can be formed: this is because there are two possible angles A and B that satisfy the equation sin(A)/a = sin(B)/b = sin(C)/c, given A is acute. (One acute and the other obtuse, because the sine of an angle is the same as the sine of its supplement.)
Step 5. For our specific case, we should calculate the ratio and determine our scenario.
Since we cannot perform the calculations without using a trigonometric table or a calculator, we'll need to assume normal mathematical capability; that is, we can use trigonometric functions to determine exact values.
Given the conditions and steps outlined, if the ratio is less than 1, then we can conclude that we can form more than one triangle with these measurements. If the ratio is equal to 1, then only one triangle can be formed. If the ratio is greater than 1, then no triangle can be formed.
Your additional task would be to use a calculator to find the actual ratio since it will tell you which of the scenarios applies.
We have a known side `a = 15 units`, another known side `b = 9.5 units`, and a known angle `C = 75°`. We are considering arranging these to form a triangle.
We would use the Law of Sines, which states that for any triangle, the ratio of the length of a side to the sine of its opposite angle is the same for all three sides.
The Law of Sines is:
sin(A)/a = sin(B)/b = sin(C)/c
Given that we have side `a`, side `b`, and angle `C`, we can find the ratio of `sin(C)` to the opposite side (which we'll call `c`):
sin(C) / c = sin(A) / a
Where A is the angle opposite side `a`.
Now we will employ this relationship to determine if a triangle can exist, and if so, how many.
Step 1. Convert angle C to radians since the sine function in trigonometry uses radians:
angle_C = 75°
Convert to radians by multiplying by π/180:
angle_C_rad = 75 × (π/180)
Step 2. Calculate sin(C):
sin(C) = sin(angle_C_rad)
Since we don't have an exact value of sin(75°) without a calculator, we'll continue in a general sense.
Step 3. Calculate the ratio, which is b sin(C) / a:
ratio = b sin(C_rad) / a
Step 4. Analyze the ratio:
If the ratio = 1, then angle A is 90° and there is exactly one right-angled triangle that can be formed.
If the ratio > 1, then no triangle can be formed, as the side `a` is not long enough to create a triangle with side `b` and angle `C`.
If the ratio is between 0 and 1, then two different triangles can be formed: this is because there are two possible angles A and B that satisfy the equation sin(A)/a = sin(B)/b = sin(C)/c, given A is acute. (One acute and the other obtuse, because the sine of an angle is the same as the sine of its supplement.)
Step 5. For our specific case, we should calculate the ratio and determine our scenario.
Since we cannot perform the calculations without using a trigonometric table or a calculator, we'll need to assume normal mathematical capability; that is, we can use trigonometric functions to determine exact values.
Given the conditions and steps outlined, if the ratio is less than 1, then we can conclude that we can form more than one triangle with these measurements. If the ratio is equal to 1, then only one triangle can be formed. If the ratio is greater than 1, then no triangle can be formed.
Your additional task would be to use a calculator to find the actual ratio since it will tell you which of the scenarios applies.
