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In the circle below, QS is a diameter . Suppose measure arc QR = 48 degrees and measure < QRT=62 degrees, find < RQS and < SRT



Answer :

pookerpooker29

Answer:

∠RQS = 24°, ∠SRT = 28°

Step-by-step explanation:

Recognize that since QS is a diameter, angle QRS is a right angle, so m∠QRS = 90°

Use the inscribed angle theorem to find m∠RQS. Since arc QR = 48°, m∠RQS = 48°/2 = 24°

Find m∠SRT by subtracting m∠QRT from 90° as QRS and QRT form a linear pair. m∠SRT = 90° - 62° = 28°

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