Answer:
x = - 10, y = 4 and x = 1, y = 2
Step-by-step explanation:
System 1
2x + 5y = 0 → (1)
2x + 3y = - 8 → (2)
subtract (2) from (1) term by term to eliminate x
(2x - 2x ) + (5y - 3y ) = 0 - (- 8)
0 + 2y = 0 + 8
2y = 8 ( divide both sides by 2 )
y = 4
substitute y = 4 into either of the 2 equations and solve for x
substituting into (1)
2x + 5(4) = 0
2x + 20 = 0 ( subtract 20 from both sides )
2x = - 20 ( divide both sides by 2 )
x = - 10
Solution to system 1 is x = - 10, y = 4
System 2
3x + 2y = 7 → (1)
2x + y = 4 → (2)
multiplying (2) by - 2 and adding the result to (1) will eliminate y
- 4x - 2y = - 8 → (3)
add (1) and (3) term by term to eliminate y
(3x - 4x ) + (2y - 2y ) = 7 - 8
- x + 0 = - 1
- x = - 1 ( multiply both sides by - 1 )
x = 1
substitute x = 1 into either of the 2 original equations and solve for y
substituting into (1)
3(1) + 2y = 7
3 + 2y = 7 ( subtract 3 from both sides )
2y = 4 ( divide both sides by 2 )
y = 2
Solution to system 2 is x = 1 , y = 2