SECTION A: Factorisation by taking out the HCF
1.1 Consider the expression: 7x+35
1.1.1 List all the terms on the expression
1.1.2 Find the HCF of these terms
1.1.3 Divide all the terms in 1.1.1 by the HCF



Answer :

Certainly! Let's go through the problem step by step.

### 1.1.1 List all the terms in the expression
The expression given is:
[tex]\[ 7x + 35 \][/tex]

The terms in this expression are:
- [tex]\( 7x \)[/tex]
- [tex]\( 35 \)[/tex]

### 1.1.2 Find the HCF of these terms
To find the Highest Common Factor (HCF), we need to consider the coefficients of the terms. The coefficients are 7 (from [tex]\( 7x \)[/tex]) and 35 (from the constant term).

Now, let’s break down the coefficients into their prime factors:
- [tex]\( 7 \)[/tex] is already a prime number.
- [tex]\( 35 \)[/tex] can be broken down into prime factors: [tex]\( 35 = 5 \times 7 \)[/tex].

The common prime factor is [tex]\( 7 \)[/tex]. Therefore, the HCF of [tex]\( 7 \)[/tex] and [tex]\( 35 \)[/tex] is [tex]\( 7 \)[/tex].

### 1.1.3 Divide all the terms by the HCF
Now, we’ll divide each term by the HCF, which is 7.

- Dividing the first term [tex]\( 7x \)[/tex] by 7:
[tex]\[ \frac{7x}{7} = x \][/tex]

- Dividing the second term [tex]\( 35 \)[/tex] by 7:
[tex]\[ \frac{35}{7} = 5 \][/tex]

So, when we factor out the HCF from the expression [tex]\( 7x + 35 \)[/tex], we get:
[tex]\[ 7x + 35 = 7(x + 5) \][/tex]

### Summary:
1. List of terms: [tex]\( 7x \)[/tex] and [tex]\( 35 \)[/tex].
2. HCF of the coefficients (7 and 35): [tex]\( 7 \)[/tex].
3. Expression after dividing each term by the HCF: [tex]\( 7(x + 5) \)[/tex].

This is the factorized form of the given expression.

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