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A child riding a bicycle at 15 m/s accelerates at 3.0 m/s^2 for 4.0 seconds. What is the child’s speed at the end of this 4.0 second interval?



Answer :

MathPhys

Answer:

27 m/s

Explanation:

We can use constant acceleration kinematics, also known as SUVAT equations, to find the child's final speed. We will use an equation that is a function of initial speed (u), acceleration (a), time (t), and final speed (v).

v = u + at

v = (15 m/s) + (3.0 m/s²) (4.0 s)

v = 27 m/s

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