When you use the distance formula, you are building a(n) _whose
hypotenuse connects two given points.
A. trapezoid
B. acute triangle
C. parallelogram
D. right triangle



Answer :

When you use the distance formula, you are building a geometric figure whose hypotenuse connects two given points. Let's explore this step-by-step:

1. The distance formula is derived from a geometric property related to a specific shape. The formula is given by:
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
where [tex]\( (x_1, y_1) \)[/tex] and [tex]\( (x_2, y_2) \)[/tex] are the coordinates of the two points.

2. The formula directly uses the coordinates to calculate the straight-line distance between the two points.

3. To derive this formula, consider two points, [tex]\( (x_1, y_1) \)[/tex] and [tex]\( (x_2, y_2) \)[/tex], plotted on a Cartesian plane.

4. Draw a horizontal line from [tex]\( (x_1, y_1) \)[/tex] to [tex]\( (x_2, y_1) \)[/tex], and then a vertical line from [tex]\( (x_2, y_1) \)[/tex] to [tex]\( (x_2, y_2) \)[/tex]. This forms a right triangle where:
- The horizontal segment measures [tex]\( |x_2 - x_1| \)[/tex]
- The vertical segment measures [tex]\( |y_2 - y_1| \)[/tex]

5. The hypotenuse of this right triangle is the straight-line distance between [tex]\( (x_1, y_1) \)[/tex] and [tex]\( (x_2, y_2) \)[/tex].

6. According to the Pythagorean theorem, for this right triangle:
[tex]\[ \text{Hypotenuse}^2 = (\text{Base})^2 + (\text{Height})^2 \][/tex]
which translates to:
[tex]\[ d^2 = (x_2 - x_1)^2 + (y_2 - y_1)^2 \][/tex]
Taking the square root of both sides gives us:
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]

Therefore, when you use the distance formula, you are essentially working with a right triangle whose hypotenuse is the distance between the two given points.

The correct answer is:
D. right triangle

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