hat is the particular solution to the differential equation start fraction, d, y, divided by, d, x, end fraction, equals, start fraction, 4, divided by, x, squared, e, start superscript, 3, y, plus, 9, end superscript, end fraction dx dy ​ = x 2 e 3y 9 4 ​ with the initial condition y, left parenthesis, 1, right parenthesis, equals, minus, 3, question marky(1)=−3?