Answer :
To find the slope of the line that contains the points (-3, -1) and (3, 3), we can use the slope formula. The slope [tex]\( m \)[/tex] of a line passing through two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is given by:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Let's assign the coordinates:
- [tex]\((x_1, y_1) = (-3, -1)\)[/tex]
- [tex]\((x_2, y_2) = (3, 3)\)[/tex]
Now plug these values into the formula:
[tex]\[ m = \frac{3 - (-1)}{3 - (-3)} \][/tex]
Simplify the numerator and the denominator:
[tex]\[ m = \frac{3 + 1}{3 + 3} \][/tex]
[tex]\[ m = \frac{4}{6} \][/tex]
Reduce the fraction to its simplest form:
[tex]\[ m = \frac{2}{3} \][/tex]
Therefore, the slope of the line that contains the points (-3, -1) and (3, 3) is:
[tex]\[ \boxed{\frac{2}{3}} \][/tex]
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]
Let's assign the coordinates:
- [tex]\((x_1, y_1) = (-3, -1)\)[/tex]
- [tex]\((x_2, y_2) = (3, 3)\)[/tex]
Now plug these values into the formula:
[tex]\[ m = \frac{3 - (-1)}{3 - (-3)} \][/tex]
Simplify the numerator and the denominator:
[tex]\[ m = \frac{3 + 1}{3 + 3} \][/tex]
[tex]\[ m = \frac{4}{6} \][/tex]
Reduce the fraction to its simplest form:
[tex]\[ m = \frac{2}{3} \][/tex]
Therefore, the slope of the line that contains the points (-3, -1) and (3, 3) is:
[tex]\[ \boxed{\frac{2}{3}} \][/tex]
